In a quadrilateral ABCD,angle A,angle B,angleC and angleD are respectively in AP and angleC=100°. Find the remaining three angles of quadrilateral
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as the angles are in A.P
we can assume
angle A = a-3d
angle B = a-d
angle C =a+d
angle D = a+3d
as the fig. is a quadrilateral
ang. A + ang. B + ang. C + ang. D =360
i.e., (a-3d) + (a-d) + (a+d) + (a+3d)=360
4a=360
a=99
also, a+d =100
or, 90+d=100
hene, d= 10
angle A = a-3d= 90-3(10)= 60
angle B = a-d = 90-10= 80
angle C = a+d = 90+10 = 100
angle D = a+3d = 90 +3(10) = 120
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