Question

in a quadrilateral ABCD angle A equal to angle B = 75° and AngleD = 110° find the angle C

Answer 1

Angle A + angle B+angleD+angleC = 360°
75+75+110+C=360°

150°+C=360°

C=360°-150°

C=210°

Answer 2

The angle C is 100°.

Step-by-step explanation:

Given : In a quadrilateral ABCD angle A equal to angle B = 75° and Angle D = 110°.

To find : The angle C ?

Solution :

We know that,

The sum of all angles of a quadrilateral is 360°.

Here, Angle A =  75°

Angle B =  75°

Angle C= x (Let)

Angle D =  110°

Now, $\angle A+\angle B+\angle C+\angle D=360^\circ$

$\angle A+\angle B+\angle C+\angle D=360^\circ$

$75^\circ+75^\circ+x+110^\circ=360^\circ$

$260^\circ+x=360^\circ$

$x=360-260$

$x=100^\circ$

The angle C is 100°.

#Learn more

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