In a quadrilateral ABCD , angle A is 125 degree less than the
straight angle. Angle B is twice of angle A and angle C is one-
fifth of angle B. Find angle D. Draw the diagram of the
quadrilateral ABCD.
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Answer:
a 125 ° and twice means 2×125×x = 250°x b and c is x and 1/5 of angle b calculate it . And no only little bit
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