Question

in a quadrilateral ABCD angle A is 75° find angle B,C,D​

Answer 1

Answer:

Opposite angles of parallelogram are equal.

∠DAB=∠BCD=75

o

and ∠DBC=60

o

∠BDC+∠DBC+∠BCD=180

o

∠BDC=180

o

−∠DBC−∠BCD=180

o

−75

o

−60

o

=45

o