In a quadrilateral ABCD angle A is 90°, sides AB and AD are respectively 9 cm, 6 cm. If the area of triangle BCD is 54 cm², then the area of quadrilateral ABCD is?
Answers
Answered by
1
Correct option is
A
369.41cm
2
Given,
ABD is a right angled triangle and
BCD is an equilateral triangle.
AB=AD
2
−BD
2
=>AB=26
−
24
2
=>AB=676−576
=>AB=
100
=>AB=10
Area of △ABC=
2
1
×AB×BD
=
2
1
×10×24
=120cm
2
Area of △BCD=
4
3
BD
2
=
4
3
×24×24
=144
3
cm
2
Area of ABCD=Area of △ABC+Area of △BCD
=120+144
3
cm
2
=369.12cm
2
Answered by
0
Answer:
81
Step-by-step explanation:
bcd=54
abd=bh/2
=9*6/2
=27
area=54+27=81cm^2
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