Question

In a quadrilateral ABCD, angle B =130 ,angle C = 60 and angle bisector of angle A and Angle D meet at P. Find angle APD.

Answer 1

I think 95 degree.................
as we know sum of opposite angel in a quadrilateral is 180.
angel ABC+angelADC=180
130+ADC=180
ADC=50

angel BCD+angelDAB=180
60+DAB=180
DAB=120
angel 1+PAB=120
angel 1=PAB............given
2of angel 1=120
angel 1=60

angel 2+PDC=50
angel 2=PDC.........given
2 of angel 2=50
angel 2=25
angel 1+ angel 2=60+25
=85


angel(1+2+APD)=180
angel APD+85=180
angel APD=95
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