Question

in a quadrilateral ABCD, angle b =130 c = 60 ,angle bisectors and d meet at p .find angle apd

Answer 1

In quad ABCD  

Angle A+B+C+D = 360 Degrees 

Angle A+D= 360-130+60 

=170 Degrees 

Angle BAC+PAD+PDA+PDC=170 Degrees 

But BAC = PAD and PDA = PDC 

2 PAD= 2 PDA 

PAD + PDA = 170/2 

PAD + PDA = 85 Degrees 

So Angle PAD+APD+APD= 180 Degrees 

APD = 180-PAD+APD 

APD= 180-85 

ANGLE APD=95 Degrees

Answer 2

please mark me BRAINLIST