Question

In a quadrilateral ABCD ANGLE B = 130 degree, angle C= 60 degree, angle bisectors of angle A and angle D meet at P. Find angle APD

Answer 1

Heya,

In quad ABCD  

Angle A+B+C+D = 360° 

Angle A+D= 360-130+60 

=170°

Angle BAC+PAD+PDA+PDC=170° 

But BAC = PAD and PDA = PDC 

=>2 PAD= 2 PDA 

PAD + PDA = 170/2 

PAD + PDA = 85° 

So Angle PAD+APD+APD= 180° 

APD = 180-PAD+APD 

APD= 180-85 

【ANGLE APD=95°】ANSWER....

HOPE IT HELPS:-))