In a quadrilateral ABCD ANGLE B = 130 degree, angle C= 60 degree, angle bisectors of angle A and angle D meet at P. Find angle APD
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Heya,
In quad ABCD
Angle A+B+C+D = 360°
Angle A+D= 360-130+60
=170°
Angle BAC+PAD+PDA+PDC=170°
But BAC = PAD and PDA = PDC
=>2 PAD= 2 PDA
PAD + PDA = 170/2
PAD + PDA = 85°
So Angle PAD+APD+APD= 180°
APD = 180-PAD+APD
APD= 180-85
【ANGLE APD=95°】ANSWER....
HOPE IT HELPS:-))
In quad ABCD
Angle A+B+C+D = 360°
Angle A+D= 360-130+60
=170°
Angle BAC+PAD+PDA+PDC=170°
But BAC = PAD and PDA = PDC
=>2 PAD= 2 PDA
PAD + PDA = 170/2
PAD + PDA = 85°
So Angle PAD+APD+APD= 180°
APD = 180-PAD+APD
APD= 180-85
【ANGLE APD=95°】ANSWER....
HOPE IT HELPS:-))
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