Question

In a quadrilateral ABCD ,angle B=130°,angle C=60°, angle bisector of angle A and angle D meet at P. Find angle APD.

riyachaurasia please solve it

Answer 1

$\frac{1}{2} \times < b + < c \\ = \frac{1}{2} \times 130 + 60 \\ = \frac{190}{2} \\ = 95 \\ \\ \\ thanks$