In a quadrilateral abcd angle b equal to 90 degree
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Step-by-step explanation:
ABCD quadrilateral,angle abc=90°
hence ab²+bc²=ac²--------(1)
ad²=(Ab²+bc²)+cd²-------given
=ac²+cd²------------(2)
In a teiangle acd ,ad has to be a hypotenuse and angle acd must be 90°as per Pythagoras theorem
hope my answer is the brainliest
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