in a quadrilateral abcd , angle C=64 angle D=angle C -degree angle A =5(a+2) degree and Angle B = 2 ( 2a+7) degree calculate angle A
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first let make the figure
c=d=64 given
angle a=5(a+2)
angle b =(2a+7)
using angle sum property
sum of all interior angle of a quadilateral = 360
angle a +angle b +angle c+angle d=360
5a+2+4a+14+64+64=360
9a+144=360
9a=360-144
9a=216
a=216/9
a=24
angle a = 5a+10=5×24+10=130degree
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