In a quadrilateral ABCD angle c=64angle d= angle c-8 angle a=5a+10 angle b= 4a+14
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Step-by-step explanation:
∠C = 64° (Given)
∴ ∠D = ∠C - 8°
= 64°- 8°
= 56°
∠A = 5 (a + 2)°
∠B = 2(2a + 7)°
Now ∠A + ∠B + ∠C + ∠D = 360°
5(a + 2)° + 2(2a + 7)° + 64°+ 56° = 360°
5a + 10 + 4a + 14° + 64° + 56° = 360°
9a + 144° = 360°
9a = 360° - 144°
9a = 216°
a = 24°
∴ ∠A = 5(a + 2)
= 5(24 + 2)
= 130°
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