In a quadrilateral ABCD, angle D is equal to 150 degree and angle A= angle B= angle C. Find the
3 angles.
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Answered by
3
Answer:
∠D = 150°
Let∠A =∠B =∠C = x
By angle sum property of quadrilateral,
∠A + ∠B + ∠C +∠D = 360°
x + x +x+∠D = 360°
3x+∠D = 360°
3x = 360°–∠D
30 = 360° – 150°
3x = 210°
x = 70°
Hence,∠A =∠B =∠C = 70°.
Thanks
Answered by
2
Answer:
The correct answer will be 70°
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