in a quadrilateral ABCD, angle of A =72 degree and angle of C is the supplementary of angle of A. The other two angles are 2x-10 and x+4.Find the value of x and the measure of all the angles.
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A=72`
C=180-72=108`
B=2x-10
D=x+4
72+108+2x-10+x+4=360
3x+174=360
3x=360-174
3x=186
x=62'
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Answered by
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Answer:
x = 62°
2x - 10= 114°
x + 4= 66°
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