Math, asked by hagelh4, 5 hours ago

In a quadrilateral ABCD, angleA=66°, angleB=(angleC+16)º: angleC = 6(x+4)º and D-(angleA-16)". Calculate angleB and D.​

Answers

Answered by ankitakri8210
0

Answer:

Step-by-step explanation:

D = A -16

D = 66- 16

D = 50°

B = 6(x+4)+16

Answered by hotgoodgirl
0

get lost why are you answering in my question duffet

Similar questions