In a quadrilateral ABCD, angleA=66°, angleB=(angleC+16)º: angleC = 6(x+4)º and D-(angleA-16)". Calculate angleB and D.
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Answer:
Step-by-step explanation:
D = A -16
D = 66- 16
D = 50°
B = 6(x+4)+16
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get lost why are you answering in my question duffet
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