Question

in a quadrilateral ABCD,angleA=72° and angleC is the supplementry of angleA. the other two angles are 2 x minus 10 and x + 4 find the value of x and the measure of all the angles.​

Answer 1

Step-by-step explanation:

A+B+C+D=360°

A+C=180°

72+C=180°

180-72 =108°

72°+108°+2x-10+x+4=360°

180°+2x-10+x+4=360°

2x-10+x+4=180°

3x-6=180°

3x=180°+6°

3x=186°

x=186°÷3

x=62

A=72°

B=114°

C=108°

D=66°