In a quadrilateral ABCD,angleA,angleB,angleC and angleD are respectively in arithmetic progression and angleC equal to 100 degree.Find the remaining 3 angles of quadrilateral
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Step-by-step explanation:
Since the sum of all angles of a quadrilateral is 360, lets consider that d is x.
Then:
Let angle A be equal to 100-2x.
Let angle B be equal to 100-x.
Let angle C be equal to 100 which is already given.
Let angle D be equal to 100+x.
Thus, we just need to compute the following equation:
(100 - 2x) + (100 - x) + (100) + (100 + x) = 360
⇔ 400-2x=360
⇔ 2x=400-360
⇔ 2x = 40
⇔ x = 20.
Then, we can conclude that our angles are:
A = 100 - 2 * 20 = 100 - 40 = 60
B = 100 - 20 = 80
D = 100 + 20 = 120
Just as a way of verification:
A+B+C+D = 360
60+80+100+120= 360
360= 360
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