Question

In a quadrilateral abcd anglea angleb anglec angled are respectively in ap and anglec=100. Find the remaining three angles of quadrilateral

Answer 1

Answer:

Step-by-step explanation:

Since ∠A,∠B and∠C are in AP

Let d is is common difference of AP then

Let ∠A=100-2d,∠B=100-d and ∠C=100,∠D=100+d

∠A+∠B+ ∠C+∠D=360

100-2d+100-d+100+100+d=360

400-2d=360

-2d=360-400

-2d=-40

d=20

Hence ∠A=100-2*20=100-40=60

∠B=100-d=100-20=80

∠C=100

∠D=100+20=120