In a quadrilateral ABCD are in the angle A= 72 degree and angle C is the supplementary of angle A. the other two angles are 2x-10 and x+4. find the value of X and the measure of all the angles.
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Answer:
angle c= 180-72=108
Step-by-step explanation:
therefore,
(2x-10)+(x+4)+72+108=360
3x+174=360
3x=360-174
3x=186
x=62
therefore,
angleA=72-given
angle B=114
angleC=108
angleD=66
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