In a quadrilateral ABCD bisectors of angle A and B intersect at O such that angle aob is equal to 75 degree then write the value of angle C + angle d
Answers
Answered by
128
angle AOB = 75°
then by using angle sum property
angle O + angle BAO + angle ABO = 180°
75° + angle BAO + angle ABO = 180°
angle BAO +angle ABO = 180° - 75°
angle BAO + angle ABO = 105°
then,
(1/2) angle A + (1/2) angle B = 105°
then,
angle A + angle B = 2 × 105°
angle A + angle B = 210°
now,
ABCD is a quadrulateral then,
angle A + angle B + angle C + angle D = 360°
210° + angle C + angle D = 360
angle C + angle D = 360 - 210°
angle C + angle D = 150°
then by using angle sum property
angle O + angle BAO + angle ABO = 180°
75° + angle BAO + angle ABO = 180°
angle BAO +angle ABO = 180° - 75°
angle BAO + angle ABO = 105°
then,
(1/2) angle A + (1/2) angle B = 105°
then,
angle A + angle B = 2 × 105°
angle A + angle B = 210°
now,
ABCD is a quadrulateral then,
angle A + angle B + angle C + angle D = 360°
210° + angle C + angle D = 360
angle C + angle D = 360 - 210°
angle C + angle D = 150°
Answered by
10
Answer:
answer is 150°
Step-by-step explanation:
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