In a quadrilateral ABCD, bisectors of angles A and B intersect at O such that ∠AOB = 75°, then write the value of ∠C + ∠D=.........
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In a quadrilateral ABCD, bisectors of angles A and B intersect at O such that ∠AOB = 75°, then write the value of ∠C + ∠D=.........
ANSWER
GIVEN,
ABCD is a quadrilateral
Bisector of A and B intersect at O
∠AOB =75°
To find :-
∠C+∠D
Proof :-
Since ,∠AOB = 75° (given)
Then ∠AOB = 1/2 (∠ADC + ∠ABC)
or ∠AOB = 1/2 (∠D + ∠C)
By substituting given values, we get
=>75° = 1/2 (∠D + ∠C)
=> ∠C + ∠D = 150
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