Math, asked by devil1237, 5 months ago

In a quadrilateral ABCD, bisectors of angles A and B intersect at O such that ∠AOB = 75°, then write the value of ∠C + ∠D=......... ​

Answers

Answered by ElegantBoy
12

Step-by-step explanation:

Question

In a quadrilateral ABCD, bisectors of angles A and B intersect at O such that ∠AOB = 75°, then write the value of ∠C + ∠D=.........

ANSWER

GIVEN,

ABCD is a quadrilateral

Bisector of A and B intersect at O

∠AOB =75°

To find :-

∠C+∠D

Proof :-

Since ,∠AOB = 75° (given)

Then ∠AOB = 1/2 (∠ADC + ∠ABC)

or ∠AOB = 1/2 (∠D + ∠C)

By substituting given values, we get

=>75° = 1/2 (∠D + ∠C)

=> ∠C + ∠D = 150

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