Question

in a quadrilateral ABCD ,CO abd DO are bisectors of angle C and angle D respectively.

Prove that angle COD = half × angle A + angle B .​

Answer 1

Answer:

Step-by-step explanation:

In △COD,

∠COD+∠1+∠2=180

o

∠COD=180

o

−(∠1+∠2)

∠COD=180

o

−

2

1

​

(∠C+∠D)

∠COD=180

o

−

2

1

​

[360

o

−(∠A+∠B)]

∠COD=

2

1

​

(∠A+∠B)

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