Question

In a quadrilateral ABCD, CO and DO are the bisectors of angle C and D respectively. Prove that angle COD=1/2(angle A+ angle B).

Answer 1

Answer

In △COD,

∠COD+∠1+∠2=180o

∠COD=180o−(∠1+∠2)

∠COD=180o−21(∠C+∠D)

∠COD=180o−21[360o−(∠A+∠B)]

∠COD=1/2(∠A+∠B)

Hope it helps you!

mark me as the brainliest