Question

in a quadrilateral ABCD diagonal AC is equals to 10 cm and length of perpendicular Form B and D to are 5 cm and 7cm respectively then its area is​

Answer 1

Given : Length of the diagonal (AC)=10 cm

Area of quadrilateral ABCD=ar(△ABC)+ar(△ACD)

=( 1/2×AC×BM)+( 1/2×AC×DL)

= 1/2 × AC ( BM + DL )

= 1/2 × 10 ( 5 + 6 )

= 5 × 11 cm^2

= 55cm ^2

Answer 2

Answer:

Given: Length of the digonal (AC)=10 cm

Area of quadrilateral ABCD=ar(△ABC)+ar(△ACD)

=(1/2×AC×BM)+(1/2×AC×DL)

=1/2×AC(BM+DL)

=1/2×10(5+6)

=5×11cm²=55cm²

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