Question

In a Quadrilateral ABCD DO and CO are the bisectors of angle D and angle C respectively. Prove that <_COD=1/2(<_A+<_B).

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

if the given figure AOB is a straight line./_AOC=(3×10)°/_COD=50° and/_BOD=[x+20]°then/_AOC