Math, asked by Abispa, 10 months ago

In a quadrilateral ABCD DO and CO are the bisectors of <D and <C respectively prove that <COD = 1/2 (<A+<B)

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Answered by shadowdevil8

0

Answer:

In a quadrilateral ABCD, CO and DO are the bisectors of ∠C and ∠D respectively. Prove that ∠COD=21(∠A+∠B).

Answered by tennetiraj86

0

Answer:

answer for the given problem is given

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