In a quadrilateral ABCD if angle B = 130° and angle C=60° and the bisectors of angle A and angle D intersect at P, then angle APD=
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Answer:
APD =95
Step-by-step explanation:
sum of angle A and D =360- 130+60
=170
since the bisectors meet point p the angle of A and D are bisected.ie, 170/2 =85
thus the sum of angles PAD and PDA =85
angle APD= 180-85
=95
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