in a quadrilateral ABCD if angle C is equals to angle b + D and ab is equals to AC then prove that AC is equals to AD
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its proved that , in a quadrilateral ABCD if ∠C = ∠B + ∠D and AB = AC then AC = AD
Step-by-step explanation:
∠ C = ∠B + ∠D
if we join AC then
∠ C = ∠ACD + ∠ ACB
now in Δ ABC
AC = AB
=> ∠ACB = ∠B
=> ∠ C = ∠ACD + ∠B
while ∠ C = ∠B + ∠D
=> ∠D = ∠ACD
in Δ ACD
∠D = ∠ACD
=> AD = AC
QED
Proved
its proved that , in a quadrilateral ABCD if ∠C = ∠B + ∠D and AB = AC then AC = AD
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3
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