IN A QUADRILATERAL ABCD IF angleA=80, angle B=95 angle C=112 find angle D
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we know that sum of all angles of a quadrilateral is 360°
so , in the given quadrilateral ABCD
angle A + angle B + angle C + angle D = 360°
=> 80°+95°+112°+angle D = 360°
=> angle D = 360-(80+95+112)
=> angle D = 360°-287° = 73°
hope this helps
so , in the given quadrilateral ABCD
angle A + angle B + angle C + angle D = 360°
=> 80°+95°+112°+angle D = 360°
=> angle D = 360-(80+95+112)
=> angle D = 360°-287° = 73°
hope this helps
Answered by
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SUM OF ALL THE ANGLES OF A QUADRILATERAL=360°
ANGLE(A+B+C+D) = 360°
80°+95°+112°+D=360°
D=360-(80°+95°+112°)
D=360-287
D=73°
ANGLE(A+B+C+D) = 360°
80°+95°+112°+D=360°
D=360-(80°+95°+112°)
D=360-287
D=73°
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