In a quadrilateral ABCD ,if triangle A,Triable B, triangle C and triangle D are in the ratio of 3:4:6:7 then the measures of the each angles of the quadrilateral are ....
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Angle A=70
Angle B=80
Angle C=100
Angle D=110
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the total sum of angles of quadrilateral is equal to 360°.
therefore,
sum of ratios given=3+4+6+7=20
so,first angle =3/20×360=54
second angle=4/20×360=72
third angle=6/20×360=108
forth angle=7/20×360=126
sum of all angles=126+108+72+54=360°
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