In a quadrilateral ABCD it is being given that AB//CD ,Angle A :Angle d =2:3 and Angle B :Angle C =4:5 then Angle D=
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Let the angle be 2x, 3x & 4y, 5y
Since AB||CD ;
angle A + angle D = 180⁰
angle B + angle C = 180⁰
2x + 3x = 180⁰
5x = 180⁰
x = 36⁰
4y + 5y = 180⁰
y = 20⁰
<A = 2x = 72⁰
<B = 4y = 80⁰
<C = 5y = 100⁰
<D = 3x = 108⁰
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