Question

In a quadrilateral ABCD, It is given that AB =

AD = 10 cm, BC = CD = 17 cm, BD = 16 cm.

If r is the radius of the circle inscribed in the

quadrilateral then what is the radius closest to

interger?​

Answer 1

Answer:

ാബ്ഹൂദബത =ിബ സ. 65×70

5× ുൂുരഹാബത

Step-by-step explanation:

തദീക്ാ५ജ