In a quadrilateral ABCD it is given that AB=AD=13, BC=CD=20,BD=24. If r is the radius of the of circle inscrible in the quadrilateral, then what is the integer closest to r
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Lets consider ABCD is a kite. Here is AC is perpendicular to BD. Finding the area of the figure is through ½ x AC x BD which comes to 252 cm square. Now. The radius can be found by area divided by S, which becomes 252 by 33 comes to 7.63 cm square. So closest is 8.
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