Math, asked by CalmlyRaging, 1 year ago

In a quadrilateral ABCD, it is given that AB=AD=13, BC=CD=24, BD=24. If r is the circle inscribable in the quadrilateral, then what is yhe integer closest to r?

It is okay if u don't answer fast... I just need the answer.... ;-):-*(^^)

Answers

Answered by Mayur8069
0
43123456789012345678

Mayur8069: 1 ÷35
Answered by amritpal3169pdrrxj
0

Real answer is r= 7.63
Closest integer is 08
Inradius in Right angle Tripuziod is equal to area divided by Semiperimeter

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