Question

In a quadrilateral ABCD < D =150° and <A=<B=<C then find the value of <A,<B,<C​

Answer 1

Answer:

<D = 150°

Then,

Sum of angles in quadrilateral = 360°

Then,

A + B + C + D = 360°

x +x + x + 150° = 360 °

3x = 360 -150

3x = 210

x = 210/3 =70°

Then, <A= <B =<C = x = 70°