Math, asked by DikshaKumari, 1 year ago

In a quadrilateral ABCD prove that:- AB+BC+CD >DA


DikshaKumari: The answer is :- AB + BC> AC -(1) ,CD+AC> DA -(2),ADDING BOTH ; AB + BC + CD +AC> AC +DA ; Therefore AB + BC + CD > DA

Answers

Answered by shivasaikrishna
2
yes by taking an example of ab=5 bc=6 cd=7 da= 8
in the we are adding the three value 5+6+7=18 
but the qusetion is posed these three are greater than this

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