Question

In a quadrilateral abcd prove that sin a + b + sin c + d is equal to zero

Answer 1

Step-by-step explanation:

= A+B +C+D = 360 degree = 2pie

= A+B = 2pie - ( C+ D )

= sin ( A+B ) = sin [ 2pie - ( C+ D ) ]

x is quadrant lV means sinx is - ve

therefore, sin ( A+ B ) = sin [ 2pie - ( C+D )] = - sin ( A+D )

hence, sin ( A+B) + sin ( C+D ) = 0

hope it helps you