Question

In a quadrilateral ABCD,sideAB is parallel to side DC.If A:D=1:2/and C:B=4:5. calculate each angle of a quadrilateral

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Answer 1

Answer:

Sorry this is to confusing for me

Step-by-step explanation:

Answer 2

Solution : Let, A=x , D=2x & C=4x , B=5x.

In quadrilateral  ABCD,

   <A + <B + <C + <D = 360

=>     x + 5x + 4x + 2x =360

=>                          12x =360

=>                            x = 360/12

=>                            x =  30

Therefore,  A = x = 30

                   D = 2x = 2 (30) = 60

                   C = 4x = 4 (30) = 120

                   B = 5x = 5 (30) = 150.