In a quadrilateral ABCD, sideAD is parallel to side BC if angle A:angle B =2:3and angle C: angle D=4:5,find each angle of quadrilateral ABCD
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firstly, A:B= 2:3
let measure of angles be X.
measure of angle a = 2x
measure of angle b = 3x.
A.T.Q.
2x+3x=180 (co-interior angles)
5x= 180
x=180/5
x=36
measure of angle a = 2x= 2*36= 72.
measure of angle b = 3x = 3*36= 108
now, C:D= 4:5
let measure of angles be X.
measure of angle C = 4x
measure of angle D = 5x.
A.T.Q.
4x+5x=180 (co-interior angles)
9x= 180
x=180/9
x=20
measure of angle C = 2x= 4*20= 80.
measure of angle b = 5x = 5*20= 100
Ans= Measure of angle A = 36, B= 108, C= 80 and D= 100.
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