Question

in a quadrilateral ABCD so and so are the bisect angle c and angle d respectively prove that angle COD is equal to 1 by 2( angle A + angle b)​

Answer 1

Step-by-step explanation:

In △COD,

∠COD+∠1+∠2=180

o

∠COD=180

o

−(∠1+∠2)

∠COD=180

o

−

2

1

(∠C+∠D)

∠COD=180

o

−

2

1

[360

o

−(∠A+∠B)]

∠COD=

2

1

(∠A+∠B)

solution