IN A QUADRILATERAL ABCD, THE ANGLE A,B,C AND D ARE IN RATIO 1:2:3:4. FIND THE MEASURE
0F EACH ANGLE OF QUADRILATERAL.
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Let the angle be x
x+2x+3x+4x=360
10x=360
x=36
So, angle a =36
angle b=2×36
angle c=3×32
angle d=4×32
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