in a quadrilateral ABCD the angle a b c and d are in ratio 1 is to 2 is to 3 is to 4 find the measure of the largest angle of the quadrilateral
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Answered by
5
let ratio be x.
so 1x + 2x + 3x + 4x = 360 (Sum of angles in a quadrilateral is 360)
10x = 360
x = 360/ 10 = 36
angle a = 1x = 1* 36 = 36
angle b = 2x = 2 * 36 = 72
angle c = 3x = 3* 36 = 108
angle d = 4x = 4* 36 = 134
so 1x + 2x + 3x + 4x = 360 (Sum of angles in a quadrilateral is 360)
10x = 360
x = 360/ 10 = 36
angle a = 1x = 1* 36 = 36
angle b = 2x = 2 * 36 = 72
angle c = 3x = 3* 36 = 108
angle d = 4x = 4* 36 = 134
Answered by
4
Answer:
Step-by-step explanation:
Let the common ratio be x.
Then the measure of four angles is 1x, 2x, 3x, 4x
We know that the sum of the angles of quadrilateral is 360°.
Therefore, x + 2x + 3x + 4x = 360°
⇒ 10x = 360°
⇒ x = 360/10
⇒ x = 36
Therefore, 1x = 1 × 36 = 36°
2x = 2 × 36 = 72°
3x = 3 × 36 = 108°
4x = 4 × 36 = 144°
Hence, the measure of the four angles is 36°, 72°, 108°, and 144°
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