in a quadrilateral ABCD, the angle is in ratio 3:4:5: 6. find the measure of each angle of a quadrilateral
hey friends pls help 9th grade
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Answered by
4
Heya!
We know that,
Sum of all angles of rectangle = 360°
Let,
<1 = 3x
<2= 4x
<3= 5x
<4= 6x
<1+<2+<3+<4= 360°
3x+4x+5x+6x =360°
18x = 360°
x= 20
So,
<1 = 3x = 3×20= 60°
<2= 4x = 4×20= 80°
<3= 5x = 5×20= 100°
<4= 6x = 6×20= 120°
:)
We know that,
Sum of all angles of rectangle = 360°
Let,
<1 = 3x
<2= 4x
<3= 5x
<4= 6x
<1+<2+<3+<4= 360°
3x+4x+5x+6x =360°
18x = 360°
x= 20
So,
<1 = 3x = 3×20= 60°
<2= 4x = 4×20= 80°
<3= 5x = 5×20= 100°
<4= 6x = 6×20= 120°
:)
shaunajay123:
thx so much happy face :)
Answered by
1
HELLO
Let the angles of quadrilateral = 3x, 4x, 5x, 6x
According to angle sum proper
3x + 4x +5x + 6x. = 360
18x = 360
x = 360/18
x = 20
3x = 3*20 = 60
4x = 4*20= 80
5x = 5*20 = 100
6x = 6*20. = 120
Hope it helped you
Let the angles of quadrilateral = 3x, 4x, 5x, 6x
According to angle sum proper
3x + 4x +5x + 6x. = 360
18x = 360
x = 360/18
x = 20
3x = 3*20 = 60
4x = 4*20= 80
5x = 5*20 = 100
6x = 6*20. = 120
Hope it helped you
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