Question

in a quadrilateral ABCD the angles A,B,C,D are in the ratio 1:2:3:4. Find the measure of each angles of the quadrilateral?​

Answer 1

Answer:

let the ratio be x

1x+2x+3x+4x=360( angle sum property of quadrilateral)

10x=360

x=360÷10

x=36

angle 1=1x=1(36)=36

angle 2=2x=2(36)=72

you find angle 3 and 4

Answer 2

Answer:

ANGLES

A = 36

B = 72

C = 108

D = 144

Step-by-step explanation:

$let \: \: the \: \: angles \: \: be \\ \: \: \: \: \: \: \: \: \: \: \: 1x \: \: 2x \: \: 3x \: \: 4x \: \\ \\ 1x + 2x + 3x + 4x = 360 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: 10x = 360 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = 36 \\ \\ \: \: \: \: \: \: 1x = 1 \times 36 = \: \: \: 36 \\ \: \: \: \: \: \: 2x = 2 \times 36 = \: \: \: 72 \\ \: \: \: \: \: \: 3x = 3 \times 36 = 108 \\ \: \: \: \: \: \: 4x = 4 \times 36 = 144$

I HOPE THIS MAY HELP YOU

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