Math, asked by Ashishteaches, 2 months ago

In a quadrilateral ABCD,the angles are in ratio 6:8:10:12. Find the measure of each angle of the quadrilateral.​

Answers

Answered by Anonymous
68

Answer:

The ratio is 6:8:10:12 then let the angles be 6x,8x,10x, and 12x.

6x+8x+12x+10x=360° [Angle sum property of quadrilateral]

36x=360°

x=360/36

x=10°

then, 6x=60

8x=80

10x=100

12x=120

Answered by Anonymous
143

Answer:

  • 1st angle = 60°
  • 2nd angle = 80°
  • 3rd angle =100°
  • 4th angle = 120°

Step-by-step explanation:

  • In a quadrilateral ABCD, the angles are in ratio 6:8:10:12.

Let the angles of the quadrilateral be 6x , 8x , 10x and 12x respectively.

We know that,

The sum of the interior angles of a quadrilateral are equal to 360°.

Then,

\implies 6x+8x+10x+12x=360°

\implies 36x = 360°

\implies x=360°/36

\implies x = 10°

Therefore,

The 4 angles,

  • 1st angle = 6×10 = 60°
  • 2nd angle = 8×10 = 80°
  • 3rd angle = 10×10= 100°
  • 4th angle = 12×10 = 120°

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