In a quadrilateral ABCD,the angles are in ratio 6:8:10:12. Find the measure of each angle of the quadrilateral.
Answers
Answered by
68
Answer:
The ratio is 6:8:10:12 then let the angles be 6x,8x,10x, and 12x.
6x+8x+12x+10x=360° [Angle sum property of quadrilateral]
36x=360°
x=360/36
x=10°
then, 6x=60
8x=80
10x=100
12x=120
Answered by
143
Answer:
- 1st angle = 60°
- 2nd angle = 80°
- 3rd angle =100°
- 4th angle = 120°
Step-by-step explanation:
- In a quadrilateral ABCD, the angles are in ratio 6:8:10:12.
Let the angles of the quadrilateral be 6x , 8x , 10x and 12x respectively.
We know that,
The sum of the interior angles of a quadrilateral are equal to 360°.
Then,
6x+8x+10x+12x=360°
36x = 360°
x=360°/36
x = 10°
Therefore,
The 4 angles,
- 1st angle = 6×10 = 60°
- 2nd angle = 8×10 = 80°
- 3rd angle = 10×10= 100°
- 4th angle = 12×10 = 120°
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