Question

In a quadrilateral abcd the bisector of b and d intersect on ac at e

Answer 1

Answer:

Step-by-step explanation:

In triangle AOB:-

m of angle AOB+m of angle OAB +m of angle OBA=180

m of angleAOB+A/2+B/2=180

m of angle AOB=[180-(A+B)/2]…………….(1)

m of angle C=C , m of angle D= D

Given that:-

m of angle C+m of angle D=k. m of angle AOB

C+D= k.[180-(A+B)/2]

(C+D)=k.[360-(A+B)]/2 In quadrilateral ABCD

A+B+C+D=360

C+D=[360-(A+B)]

[360-(A+B)]=k.[360-(A+B)]/2

1=k/2 or k=2 , answer.