Math, asked by BlaBlaBlaBlaBlaBla, 1 year ago

In a quadrilateral ABCD the point O denotes the intersection of the diagonals. The perimeters of the triangles AOB, BOC, COD and DOA are equal. Prove that ABCD is a rhombus.

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Answered by MuskanS1
0
i hope it is righttt
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BlaBlaBlaBlaBlaBla: I don't think so you can cancle like this.
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