In a quadrilateral ABCD, there is a point O inside it such that OB =OD Also, AB = AD and BC =DC prove that O lies on AC.
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Step-by-step explanation:
AB = AD => ΔABD is isosceles
=> A is on the perpendicular bisector of BD
BC = DC => ΔCBD is isosceles
=> C is on the perpendicular bisector of BD
OB = OD => ΔOBD is isosceles
=> O is on the perpendicular bisector of BD
So points A, C, O all lie on the same line (the line AC).
That is, O lies on AC.
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