Question

In a quadrilateral ABCD, ZA = 150° ZB= ZC=ZD, Find ZB, ZC, ZD​

Answer 1

Answer:

of the park be x

Then according to the question,

Breadth=x+26 and 2(x+x+26)=400 (perimeter is 400m)

2x+26=200

Step-by-step explanation:

Answer 2

Answer:

70

Step-by-step explanation:

we know ,

in a quad , sum of measures of all angles is 360°

ang A + ang B + ang C + ang D = 360°

150 + B + C + D = 360

B + C + D = 360 - 150 = 210

B + B + B = 210 ........(B = C = D)

3B = 210

B = 210/3

B = 70

similarly C = 70

D = 70

hope it helps