Question

in a quadrilateral acbd ac=ad and ab bisects angle a show that triangle abc congruent to triangle abd
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Answer 1

Answer:

InΔABCandΔABD

∠CAB=∠DAB(given)

AC=AB(common)

so,ΔABC≅ΔABD(bySAScriterion)

Now,

ΔABC≅ΔABD

⇒BC=BD(byc.p)

Answer 2

Question :-

In quadrilateral ACBD, AC = AD and AB bisects ∠ A (see figure). Show that ∆ABC ≅ ∆ABD. What can you say about BC and BD?

Answer :-

In quadrilateral ACBD, we have AC = AD and AB being the bisector of ∠A.

Now, In ∆ABC and ∆ABD,

AC = AD (Given)

∠ CAB = ∠ DAB ( AB bisects ∠ CAB)

and AB = AB (Common)

∴ ∆ ABC ≅ ∆ABD (By SAS congruence axiom)

∴ BC = BD (By CPCT)

Plz mrk as brainliest ❤